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Infinitary Logic

Traditionally, expressions in formal systems have been regarded as signifying finite inscriptions which are--at least in principle--capable of actually being written out in primitive notation. However, the fact that (first-order) formulas may be identified with natural numbers (via "Gödel numbering") and hence with finite sets makes it no longer necessary to regard formulas as inscriptions, and suggests the possibility of fashioning "languages" some of whose formulas--such as that in the above quotation--would be naturally identified as infinite sets. A "language" of this kind is called an infinitary language: in this article we discuss those infinitary languages which can be obtained in a straightforward manner from first-order languages by allowing conjunctions, disjunctions and, possibly, quantifier sequences, to be of infinite length. In the course of the discussion we shall see that, while the expressive power of such languages far exceeds that of their finitary (first-order) counterparts, very few of them possess the "attractive" features (e.g., compactness and completeness) of the latter. Accordingly, the infinitary languages that do in fact possess these features merit special attention.

In §1 we lay down the basic syntax and semantics of infinitary languages and demonstrate their expressive power by means of examples. §2 is devoted to those infinitary languages which permit only finite quantifier sequences: these languages turn out to be relatively well-behaved. In §3 we discuss the compactness problem for infinitary languages and its connection with purely set-theoretical questions concerning "large" cardinal numbers. In §4 an argument is sketched which shows that most "infinite quantifier" languages have a second-order nature and are, ipso facto, highly incomplete. In §5 we give a brief account of a certain special class of sublanguages of infinitary languages for which a satisfactory generalization of the compactness theorem can be proved. (This section links to a Supplement on the definition of admissible sets.) We conclude with historical and bibliographical remarks in §6.


1. Definition and Basic Properties of Infinitary Languages

Given a pair , of infinite cardinals such that , we define a class of infinitary languages in each of which we may form conjunctions and disjunctions of sets of formulas of cardinality < , and quantifications over sequences of variables of length < .

Let -- the (finitary) base language -- be an arbitrary but fixed first-order language with any number of extralogical symbols. The infinitary language (, ) has the following basic symbols:

The class of preformulas of (, ) is defined recursively as follows: If is a set of preformulas indexed by a set I, say = {i : i I}, then we agree to write for:
or, if I is the set of natural numbers, we write for:
0 1 ...

If X is a set of individual variables indexed by an ordinal , say X = {x : < }, we agree to write (x)< for X.

The logical operators , , are defined in the customary manner. We also introduce the operators (infinitary disjunction) and (universal quantification) by

=df { : }

X =df X,

and employ similar conventions as for , .

Thus (,) is the infinitary language obtained from by permitting conjunctions and disjunctions of length < and quantifications[1] of length < . Languages (,) are called finite-quantifier languages, the rest infinite-quantifier languages. Observe that (,) is just itself.

Notice the following anomaly which can arise in an infinitary language but not in a finitary one. In the language (1,), which allows countably infinite conjunctions but only finite quantifications, there are preformulas with so many free variables that they cannot be "closed" into sentences of (1,) by prefixing quantifiers. Such is the case, for example, for the (1,)-preformula

x0 < x1    x1 < x2    ...    xn < xn+1 ...,
where contains the binary relation symbol <. For this reason we make the following
Definition. A formula of (,) is a preformula which contains < free variables. The set of all formulas of (,) will be denoted by Form((,)) or simply Form(,) and the set of all sentences by Sent((,)) or simply Sent(,).
In this connection, observe that, in general, nothing would be gained by considering "languages" (,) with > . For example, in the "language" (,1), formulas will have only finitely many free variables, while there will be a host of "useless" quantifiers able to bind infinitely many free variables.[2]

Having defined the syntax of (,), we next sketch its semantics. Since the extralogical symbols of (,) are just those of , and it is these symbols which determine the form of the structures in which a given first-order language is to be interpreted, it is natural to define an (,)-structure to be simply an -structure. The notion of a formula of (,) being satisfied in an -structure A (by a sequence of elements from the domain of A) is defined in the same inductive manner as for formulas of except that we must add two extra clauses corresponding to the clauses for and X in the definition of preformula. In these two cases we naturally define:

is satisfied in A (by a given sequence)    for all , is satisfied in A (by the sequence);

X is satisfied in A    there is a sequence of elements from the domain of A in bijective correspondence with X which satisfies in A.

These informal definitions need to be tightened up in a rigorous development, but their meaning should be clear to the reader. Now the usual notions of truth, validity, satisfiability, and model for formulas and sentences of (,) become available. In particular, if A is an -structure and Sent(,), we shall write A for A is a model of , and for is valid, that is, for all A, A. If Sent(,), we shall write for is a logical consequence of , that is, each model of is a model of .

We now give some examples intended to display the expressive power of the infinitary languages (,) with 1. In each case it is well-known that the notion in question cannot be expressed in any first-order language.

Characterization of the standard model of arithmetic in (1,). Here the standard model of arithmetic is the structure N = (N, +, , s, 0), where N is the set of natural numbers, +, , and 0 have their usual meanings, and s is the successor operation. Let be the first-order language appropriate for N. Then the class of -structures isomorphic to N coincides with the class of models of the conjunction of the following (1,) sentences (where 0 is a name of 0):

The terms snx are defined recursively by s0x = x; sn+1x = s(snx).

Characterization of the class of all finite sets in (1,). Here the base language has no extralogical symbols. The class of all finite sets then coincides with the class of models of the (1,)-sentence

v0 ... vnx(x = v0 ... x = vn).

Truth definition in (1,) for a countable base language . Let be a countable first-order language (for example, the language of arithmetic or set theory) which contains a name n for each natural number n, and let 0, 1, ... be an enumeration of its sentences. Then the (1,)-formula

Tr(x)  =df  (x = n n)
is a truth predicate for inasmuch as the sentence
Tr(n) n
is valid for each n.

Characterization of well-orderings in (1,1). The base language here includes a binary predicate symbol . Let 1 be the usual -sentence characterizing linear orderings. Then the class of -structures in which the interpretation of is a well-ordering coincides with the class of models of the (1,1) sentence = 1 2, where

2 =df (vn)n x [ (x = vn) (x vn)].
Notice that the sentence 2 contains an infinite quantifier: it expresses the essentially second-order assertion that every countable subset has a least member. It can in fact be shown that the presence of this infinite quantifier is essential: the class of well-ordered structures cannot be characterized in any finite-quantifier language. This example indicates that infinite-quantifier languages such as (1,1) behave rather like second-order languages; we shall see that they share the latters' defects (incompleteness) as well as some of their advantages (strong expressive power).

Many extensions of first-order languages can be translated into infinitary languages. For example, consider the generalized quantifier language (Q0) obtained from by adding a new quantifier symbol Q0 and interpreting Q0x(x) as there exist infinitely many x such that (x). It is easily seen that the sentence Q0x(x) has the same models as the (1,)-sentence

v0...vnx[(x) (x = v0 ... x = vn)].
Thus (Q0) is, in a natural sense, translatable into (1,). Another language translatable into (1,) in this sense is the weak second-order language obtained by adding a countable set of monadic predicate variables to which are then interpreted as ranging over all finite sets of individuals.

2. Finite-Quantifier Languages

We have remarked that infinite-quantifier languages such as (1,1) resemble second-order languages inasmuch as they allow quantification over infinite sets of individuals. The fact that this is not permitted in finite-quantifier languages suggests that these may be in certain respects closer to their first-order counterparts than might be evident at first sight. We shall see that this is indeed the case, notably in the case of (1,).

The language (1,) occupies a special place among infinitary languages because--like first-order languages--it admits an effective deductive apparatus. In fact, let us add to the usual first-order axioms and rules of inference the new axiom scheme

for any countable set Form(1,) and any , together with the new rule of inference
0, 1, ..., n, ...

        n
and allow deductions to be of countable length. Writing * for deducibility in this sense, we then have the
(1,)-Completeness Theorem. For any Sent(1,),    *
As an immediate corollary we infer that this deductive apparatus is adequate for deductions from countable sets of premises in (1,). That is, with the obvious extension of notation, we have, for any countable set Sent(1,)
(2.1)     *
This completeness theorem can be proved by modifying the usual Henkin completeness proof for first-order logic, or by employing Boolean-algebraic methods. Similar arguments, applied to suitable further augmentations of the axioms and rules of inference, yield analogous completeness theorems for many other finite-quantifier languages.

If just deductions of countable length are admitted, then no deductive apparatus for (1,) can be set up which is adequate for deductions from arbitrary sets of premises, that is, for which (2.1) would hold for every set Sent(1,), regardless of cardinality. This follows from the simple observation that there is a first-order language and an uncountable set of (1,)-sentences such that has no model but every countable subset of does. To see this, let be the language of arithmetic augmented by 1 new constant symbols {c : < 1} and let be the set of (1,)-sentences {} {c c : }, where is the (1,)-sentence characterizing the standard model of arithmetic. This example also shows that the compactness theorem fails for (1,) and so also for any (,) with 1.

Another result which holds in the first-order case but fails for (,) with 1 (and also for (1,1), although this is more difficult to prove) is the prenex normal form theorem. A sentence is prenex if all its quantifiers appear at the front; we give an example of an (1,)-sentence which is not equivalent to a conjunction of prenex sentences. Let be the first-order language without extralogical symbols and let be the (1,)-sentence which characterizes the class of finite sets. Suppose that were equivalent to a conjunction

iI i
of prenex (1,)-sentences i. Then each i is of the form
Q1x1 ... Qnxn i(x1,..., xn),
where each Qk is or and i is a (possibly infinitary) conjunction or disjunction of formulas of the form xk = xl or xk xl. Since each i is a sentence, there are only finitely many variables in each i, and it is easy to see that each i is then equivalent to a first-order formula. Accordingly each i may be taken to be a first-order sentence. Since is assumed to be equivalent to the conjunction of the i, it follows that and the set = {i : i I} have the same models. But obviously , and hence also , have models of all finite cardinalities; the compactness theorem for sets of first-order sentences now implies that , and hence also , has an infinite model, contradicting the definition of .

Turning to the Löwenheim-Skolem theorem, we find that the downward version has adequate generalizations to (1,) (and, indeed, to all infinitary languages). In fact, one can show in much the same way as for sets of first-order sentences that if Sent(1,) has an infinite model of cardinality ||, it has a model of cardinality the larger of 0 , ||. In particular, any (1,)-sentence with an infinite model has a countable model.

On the other hand, the upward Löwenheim-Skolem theorem in its usual form fails for all infinitary languages. For example, the (1,)-sentence characterizing the standard model of arithmetic has a model of cardinality 0 but no models of any other cardinality. However, all is not lost here, as we shall see.

We define the Hanf number h(L) of a language L to be the least cardinal such that, if an L-sentence has a model of cardinality , it has models of arbitrarily large cardinality. The existence of h(L) is readily established. For each L-sentence not possessing models of arbitrarily large cardinality let () be the least cardinal such that does not have a model of cardinality . If is the supremum of all the (), then, if a sentence of L has a model of cardinality , it has models of arbitrarily large cardinality.

Define the cardinals () recursively by

(0) = 0

(+1) = 2()

() = () for limit .

Then it can be shown that
h((1,)) = (1),
similar results holding for other finite-quantifier languages. The values of the Hanf numbers of infinite-quantifier languages such as (1,1) are sensitive to the presence or otherwise of large cardinals, but must in any case greatly exceed that of (1,).

A result for which generalizes to (1,) but to no other infinitary language is the

Craig Interpolation Theorem: If , Sent(1,) are such that , then there is Sent(1,) such that and , and each extralogical symbol occurring in occurs in both and .
The proof is a reasonably straightforward extension of the first-order case.

Finally, we mention one further result which generalizes nicely to (1,) but to no other infinitary language. It is well known that, if A is any finite -structure with only finitely many relations, there is an -sentence characterizing A up to isomorphism. For (1,) we have the following generalization known as

Scott's Isomorphism Theorem. If A is a countable -structure with only countably many relations, then there is an (1,)-sentence whose class of countable models coincides with the class of -structures isomorphic with A.
The restriction to countable structures is essential because countability cannot in general be expressed by an (1,)-sentence.

3. The Compactness Property

As we have seen, the compactness theorem in its usual form fails for all infinitary languages. Nevertheless, it is of some interest to determine whether infinitary languages satisfy some suitably modified version of the theorem. This so-called compactness problem turns out to have a natural connection with purely set-theoretic questions involving "large" cardinal numbers.

We construct the following definition. Let be an infinite cardinal. A language L is said to be -compact (resp. weakly -compact) if whenever is a set of L-sentences (resp. a set of L-sentences of cardinality ) and each subset of of cardinality < has a model, so does . Notice that the usual compactness theorem for is precisely the assertion that is -compact. One reason for according significance to the -compactness property is the following. Call L -complete (resp. weakly -complete) if there is a deductive system P for L with deductions of length < such that, if is a P-consistent[3] set of L-sentences (resp. such that || ), then has a model. Observe that such a P will be adequate for deductions from arbitrary sets of premises (of cardinality ) in the sense of §2. It is easily seen that if L is -complete or weakly -complete, then L is -compact or weakly -compact. Thus, if we can show that a given language is not (weakly) -compact, then there can be no deductive system for it with deductions of length < adequate for deductions from arbitrary sets of premises (of cardinality ).

It turns out, in fact, that most languages (, ) fail to be even weakly -compact, and, for those that are, must be an exceedingly large cardinal. We shall need some definitions.

An infinite cardinal is said to be weakly inaccessible if

(a) < + < , (where + denotes the cardinal successor of ), and

(b) |I| < and i < (for all i I) i < .

If in addition
(c) < 2 < ,
then is said to be (strongly) inaccessible. Since 0 is inaccessible, it is normal practice to confine attention to those inaccessible, or weakly inaccessible, cardinals that exceed 0. Accordingly, inaccessible or weakly inaccessible cardinals will always be taken to be uncountable. It is clear that such cardinals--if they exist--must be extremely large; and indeed the Gödel incompleteness theorem implies that the existence of even weakly inaccessible cardinals cannot be proved from the usual axioms of set theory.

Let us call a cardinal compact (resp. weakly compact) if the language (,) is -compact (resp. weakly -compact). Then we have the following results:

(3.1) 0 is compact. This is, of course, just a succinct way of expressing the compactness theorem for first-order languages.

(3.2) is weakly compact (,) is weakly -compact is weakly inaccessible. Accordingly, it is consistent (with the usual axioms of set theory) to assume that no language (,) with 1 is weakly -compact, or, a fortiori, weakly -complete.

(3.3) Suppose is inaccessible. Then is weakly compact    (,) is weakly -compact. Also, Also is weakly compact there is a set of inaccessibles before . Thus a weakly compact inaccessible cardinal is exceedingly large; in particular it cannot be the first, second, ..., nth, ... inaccessible.

(3.4) is compact is inaccessible. (But, by the result immediately above, the converse fails.)

Let Constr stand for Gödel's axiom of constructibility; recall that Constr is consistent with the usual axioms of set theory.
(3.5) If Constr holds, then there are no compact cardinals.

(3.6) Assume Constr and let be inaccessible. Then is weakly compact (1,) is weakly -compact for all .

(3.7) If Constr holds, then there are no cardinals for which (1,) is compact. Accordingly, it is consistent with the usual axioms of set theory to suppose that there is no cardinal such that all languages (1,) are -complete. This result is to be contrasted with the fact that all first-order languages are -complete.

The import of these results is that the compactness theorem fails very badly for most languages (,) with 1.

Some historical remarks are in order here. In the 1930s mathematicians investigated various versions of the so-called measure problem for sets, a problem which arose in connection with the theory of Lebesgue measure on the continuum. In particular, the following very simple notion of measure was formulated. If X is a set, a (countably additive two-valued nontrivial) measure on X is a map on the power set PX to the set {0, 1} satisfying:

(a) (X) = 1,

(b) ({x}) = () = 0 for all x X, and

(c) if A is any countable family of subsets of X, then (A) = {(Y): Y A}.

Obviously, whether a given set supports such a measure depends only on its cardinality, so it is natural to define a cardinal to be measurable if all sets of cardinality support a measure of this sort. It was quickly realized that a measurable cardinal must be inaccessible, but the falsity of the converse was not established until the 1960s when Tarski showed that measurable cardinals are weakly compact and his student Hanf showed that the first, second, etc. inaccessibles are not weakly compact (cf. (3.3)). Although the conclusion that measurable cardinals must be monstrously large is now normally proved without making the detour through weak compactness and infinitary languages, the fact remains that these ideas were used to establish the result in the first instance.

4. Incompleteness of Infinite-Quantifier Languages

Probably the most important result about first-order languages is the Gödel completeness theorem which of course says that the set of all valid formulas of any first-order language can be generated from a simple set of axioms by means of a few straightforward rules of inference. A major consequence of this theorem is that, if the formulas of are coded as natural numbers in some constructive way, then the set of (codes of) valid sentences is recursively enumerable. Thus, the completeness of a first-order language implies that the set of its valid sentences is definable in a particularly simple way. It would accordingly seem reasonable, given an arbitrary language L, to turn this implication around and suggest that, if the set of valid L-sentences is not definable in some simple fashion, then no meaningful completeness result can be established for L, or, as we shall say, that L is incomplete. In this section we are going to employ this suggestion in sketching a proof that "most" infinite quantifier languages are incomplete in this sense.

Let us first introduce the formal notion of definability as follows. If L is a language, A an L-structure, and X a subset of the domain A of A, we say that X is definable in A by a formula (x, y1, . . . , yn) of L if there is a sequence a1, . . . , an of elements of A such that X is the subset of all elements x A for which (x, a1, . . . , an) holds in A.

Now write Val(L) for the set of all the valid L-sentences, i.e., those that hold in every L-structure. In order to assign a meaning to the statement "Val(L) is definable", we have to specify

(i) a structure C(L)--the coding structure for L;

(ii) a particular one-one map--the coding map--of the set of formulas of L into the domain of C(L).

Then, if we identify Val(L) with its image in C(L) under the coding map, we shall interpret the statement "Val(L) is definable" as the statement "Val(L), regarded as a subset of the domain of C(L), is definable in C(L) by a formula of L."

For example, when L is the first-order language of arithmetic, Gödel originally used as coding structure the standard model of arithmetic and as coding map the well-known function obtained from the prime factorization theorem for natural numbers. The recursive enumerability of Val() then means simply that the set of codes ("Gödel numbers") of members of Val() is definable in by an -formula of the form y(x, y), where (x, y) is a recursive formula.

Another, equivalent, coding structure for the first-order language of arithmetic is the structure[4] <H(), | H()> of hereditarily finite sets, where a set x is hereditarily finite if x, its members, its members of members, etc., are all finite. This coding structure takes account of the fact that first-order formulas are naturally regarded as finite sets.

Turning now to the case in which L is an infinitary language (,), what would be a suitable coding structure in this case? We remarked at the beginning that infinitary languages were suggested by the possibility of thinking of formulas as set-theoretical objects, so let us try to obtain our coding structure by thinking about what kind of set-theoretical objects we should take infinitary formulas to be. Given the fact that, for each Form(,), and its subformulas, subsubformulas, etc., are all of length < [5], a moment's reflection reveals that formulas of (,) "correspond" to sets x hereditarily of cardinality < in the sense that x, its members, its members of members, etc., are all of cardinality < . The collection of all such sets is written H(). H() is the collection of hereditarily finite sets introduced above, and H(1) that of all hereditarily countable sets.

For simplicity let us suppose that the only extralogical symbol of the base language is the binary predicate symbol (the discussion is easily extended to the case in which contains additional extralogical symbols). Guided by the remarks above, as coding structure for (,) we take the structure,

() =df <H(), | H()>.

Now we can define the coding map of Form(,) into (). First, to each basic symbol s of (,) we assign a code object s H() as follows. Let {v: < } be an enumeration of the individual variables of (,).

Symbol Code Object Notation
1
2
3
4
5
= 6 =
v <0,> v
Then, to each Form(,) we assign the code object recursively as follows:
v = v  =df  <v, =, v>,

v v  =df  <v, , v>;

for , Form(,),
 =df  <, , >

 =df  <, >

X  =df  <, {x: x X}, >;

and finally if Form(,) with | | < ,
 =df  <, {: }>.

The map from Form(,) into H() is easily seen to be one-one and is the required coding map. Accordingly, we agree to identify Val((,)) with its image in H() under this coding map.

When is Val((,)) a definable subset of ()? In order to answer this question we require the following definitions.

An -formula is called a 0-formula if it is equivalent to a formula in which all quantifiers are of the form xy or xy (i.e., x(xy ...) or x(xy ...)). An -formula is a 1-formula if it is equivalent to one which can be built up from atomic formulas and their negations using only the logical operators , , xy, x. A subset X of a set A is said to be 0 (resp. 1) on A if it is definable in the structure <A, | A> by a 0- (resp. 1-) formula of .

For example, if we identify the set of natural numbers with the set H() of hereditarily finite sets in the usual way, then for each X H() we have:

X is 0 on H() X is recursive

X is 1 on H() X is recursively enumerable.

Thus the notions of 0- and 1-set may be regarded as generalizations of the notions of recursive and recursively enumerable set, respectively.

The completeness theorem for implies that Val() -- regarded as a subset of H() -- is recursively enumerable, and hence 1 on H(). Similarly, the completeness theorem for (1,) (see §2) implies that Val((1,)) -- regarded as a subset of H(1) -- is 1 on H(1). However, this pleasant state of affairs collapses completely as soon as (1,1) is reached. For one can prove

Scott's Undefinability Theorem for (1,1). Val((1,1)) is not definable in (1) even by an (1,1)-formula; hence a fortiori Val((1,1)) is not 1 on H(1).
This theorem is proved in much the same way as the well-known result that the set of (codes of ) valid sentences of the second-order language of arithemetic 2 is not second-order definable in its coding structure . To get this latter result, one first observes that is characterized by a single 2-sentence, and then shows that, if the result were false, then "truth in " for 2-sentences would be definable by an 2-formula, thereby violating Tarski's theorem on the undefinability of truth.

Accordingly, to prove Scott's undefinability theorem along the above lines, one needs to establish:

(4.1) Characterizability of the coding structure (1) in (1,1): there is an (1,1)-sentence 0 such that, for all -structures A,
A 0    A (1).

(4.2) Undefinability of truth for (1,1)-sentences in the coding structure: there is no (1,1)-formula (v0) such that, for all (1, 1)-sentences ,

(1) ().

(4.3) There is a term t(v0, v1) of (1,1) such that, for each pair of sentences , of (1,1),

(1)    t(,) = .
(4.1) is proved by analyzing the set-theoretic definition of (1) and showing that it can be "internally" formulated in (1,1). (4.2) is established in much the same way as Tarski's theorem on the undefinability of truth for first- or second-order languages. (4.3) is obtained by formalizing the definition of the coding map in (1,1).

Armed with these facts, we can obtain Scott's undefinability theorem in the following way. Suppose it were false; then there would be an (1,1)-formula (v0) such that, for all (1,1)-sentences ,

(4.4) (1) ()    Val((1,1)).
Let 0 be the sentence given in (4.1). Then we have, for all (1,1)-sentences ,
(1)    0 Val((1,1)),
so that, by (4.4),
(1)    (1) (0 ).
If t is the term given in (4.3), it would follow that
(1) (t(0, )).
Now write (v0) for the (1,1)-formula (t(0, )). Then
(1) (),
contradicting (4.2), and completing the proof.

Thus Val((1,1)) is not definable even by an (1,1)-formula, so a fortiori (1,1) is incomplete. Similar arguments show that Scott's undefinability theorem continues to hold when 1 is replaced by any successor cardinal +; accordingly the languages (+,+) are all incomplete.[6]

5. Sublanguages of (1,) and the Barwise Compactness Theorem

Given what we now know about infinitary languages, it would seem that (1,) is the only one to be reasonably well behaved. On the other hand, the failure of the compactness theorem to generalize to (1,) in any useful fashion is a severe drawback as far as applications are concerned. Let us attempt to analyze this failure in more detail.

Recall from §4 that we may code the formulas of a first-order language as hereditarily finite sets, i.e., as members of H(). In that case each finite set of (codes of) -sentences is also a member of H(), and it follows that the compactness theorem for can be stated in the form:

(5.1) If Sent() is such that each subset 0 , 0 H() has a model, so does .
Now it is well-known that (5.1) is an immediate consequence of the generalized completeness theorem for , which, stated in a form similar to that of (5.1), becomes the assertion:
(5.2) If Sent() and Sent() satisfy , then there is a deduction D of from such that D H().[7]
In §2 we remarked that the compactness theorem for (1,) fails very strongly; in fact, we constructed a set Sent(1,) such that
(5.3) Each countable subset of has a model but does not.
Recall also that we introduced the notion of deduction in (1,); since such deductions are of countable length it quickly follows from (5.3) that
(5.4) There is a sentence[8] Sent(1,) such that , but there is no deduction of in (1,) from .
Now the formulas of (1, ) can be coded as members of (1), and it is clear that (1) is closed under the formation of countable subsets and sequences. Accordingly (5.3) and (5.4) may be written:
(5.3 bis) Each 0 such that 0 (1) has a model, but does not;

(5.4 bis) There is a sentence Sent(1,) such that , but there is no deduction D H(1) of from .

It follows that (5.1) and (5.2) fail when "" is replaced by "(1,)" and "()" by "(1)". Moreover, it can be shown that the set Sent(1,) in (5.3 bis) and (5.4 bis) may be taken to be 1 on H(1). Thus the compactness and generalized completeness theorems fail even for 1-sets of (1, )-sentences.

We see from (5.4 bis) that the reason why the generalized completeness theorem fails for 1-sets in (1,) is that, roughly speaking, H(1) is not "closed" under the formation of deductions from 1-sets of sentences in H(1). So in order to remedy this it would seem natural to replace H(1) by sets A which are, in some sense, closed under the formation of such deductions, and then to consider just those formulas whose codes are in A.

We now give a sketch of how this can be done.

First, we identify the symbols and formulas of (1,) with their codes in H(1), as in §4. For each countable transitive[9] set A, let

A = Form((1,)) A.
We say that A is a sublanguage of (1,) if the following conditions are satisfied:
(i) A

(ii) if , A, then A and A

(iii) if A and x A, then x A

(iv) if (x) A and y A, then (y) A

(v) if A, every subformula of is in A

(vi) if A and A, then A.

The notion of deduction in A is defined in the customary way; if is a set of sentences of A and A, then a deduction of from in A is a deduction of from in (1, ) every formula of which is in A. We say that is deducible from in A if there is a deduction D of from in A; under these conditions we write A . In general, D will not be a member of A; in order to ensure that such a deduction can be found in A it will be necessary to impose further conditions on A.

Let A be a countable transitive set such that A is a sublanguage of (1, ) and let be a set of sentences of A. We say that A (or, by abuse of terminology, A) is -closed if, for any formula of A such that A , there is a deduction D of from such that D A. It can be shown that the only countable language which is -closed for arbitrary is the first-order language , i.e., when A = H(). However J. Barwise discovered that there are countable sets A H(1) whose corresponding languages A differ from and yet are -closed for all 1-sets of sentences . Such sets A are called admissible sets; roughly speaking, they are extensions of the hereditarily finite sets in which recursion theory--and hence proof theory--are still possible.[10]

From Barwise's result one obtains immediately the

Barwise Compactness Theorem. Let A be a countable admissible set and let be a set of sentences of A which is 1 on A. If each such that A has a model, then so does .
The presence of "1" here indicates that this theorem is a generalization of the compactness theorem for recursively enumerable sets of sentences.

Another version of the Barwise compactness theorem, useful for constructing models of set theory, is the following. Let ZFC be the usual set of axioms for Zermelo-Fraenkel set theory, including the axiom of choice. Then we have:

5.5. Theorem. Let A be a countable transitive set such that A = <A, | A> is a model of ZFC. If is a set of sentences of A which is definable in A by a formula of the language of set theory and if each such that A has a model, so does .
To conclude, we give a simple application of this theorem. Let A = <A, | A> be a model of ZFC. A model B = <B, E> of ZFC is said to be a proper end-extension of A if (i) A B, (ii) A B, (iii) a A, b B, bEa bA. Thus a proper end-extension of a model of ZFC is a proper extension in which no "new" element comes "before" any "old" element. As our application of 5.5 we prove
5.6. Theorem. Each countable transitive model of ZFC has a proper end-extension.

Proof. Let A = <A, | A> be a transitive model of ZFC and let be the first-order language of set theory augmented by a name a for each a A, and an additional constant c. Let be the set of A-sentences comprising:

It is easily shown that is a subset of A which is definable in A by a formula of the language of set theory. Also, each subset such that A has a model. For the set C of all a A for which a occurs in belongs to A -- since does -- and so, if we interpret c as any member of the (necessarily nonempty) set A - C, then A is a model of . Accordingly, (5.5) implies that has a model <B, E>. If we interpret each constant a as the element a A, then <B, E> is a proper end-extension of A. The proof is complete.
The reader will quickly see that the first-order compactness theorem will not yield this result.

[Supplement: Definition of the Concept of Admissible Set

6. Historical and Bibliographical Remarks

§§1 and 2. Infinitary propositional and predicate languages seem to have made their first explicit appearance in print with the papers of Scott and Tarski [1958] and Tarski [1958]. The completeness theorem for (1,), as well as for other infinitary languages, was proved by Karp [1964]. The Hanf number calculations for (1,) were first performed by Morley [1965]. The nondefinability of well-orderings in finite-quantifier languages was proved by Karp [1965] and Lopez-Escobar [1966]. The interpolation theorem for (1,) was proved by Lopez-Escobar [1965] and Scott's isomorphism theorem for (1,) by Scott [1965].

§3. Results (3.2) and (3.3) are due to Hanf [1964], with some refinements by Lopez-Escobar [1966] and Dickmann [1975], while (3.4) was proved by Tarski. Result (3.5) is due to Scott [1961], (3.6) to Bell [1970] and [1972]; and (3.7) to Bell [1974]. Measurable cardinals were first considered by Ulam [1930] and Tarski [1939]. The fact that measurable cardinals are weakly compact was noted in Tarski [1962].

§4. The undecidability theorem for (1,1) was proved by Scott in 1960; a fully detailed proof first appeared in Karp [1964]. The approach to the theorem adopted here is based on the account given in Dickmann [1975].

§5. The original motivation for the results presented in this section came from Kreisel; in his [1965] he pointed out that there were no compelling grounds for choosing infinitary formulas solely on the grounds of "length", and proposed instead that definability or "closure" criteria be employed. Kreisel's suggestion was taken up with great success by Barwise [1967], where his compactness theorem was proved. The notion of admissible set is due to Platek [1966]. Theorem (5.6) is taken from Keisler [1974]. For further reading on the subject of infinitary languages, see Aczel [1973], Dickmann [1975], Karp [1964], Keisler [1974], and Makkai [1977].

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John L. Bell
jbell@julian.uwo.ca

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